有时我们需要找出两个表中不匹配的数据，尤其是在数据迁移的情况下。可以通过比较表格来完成。考虑下面的示例，其中我们有两个名为“students”和“student1”的表。

mysql> Select * from students;
+--------+--------+----------+
| RollNo | Name   | Subject  |
+--------+--------+----------+
|    100 | Gaurav | Computer |
|    101 | Raman  | History  |
|    102 | Somil  | Computer |
+--------+--------+----------+
3 rows in set (0.00 sec)

mysql> select * from student1;
+--------+--------+----------+
| RollNo | Name | Subject |
+--------+--------+----------+
|    100 | Gaurav | Computer |
|    101 | Raman  | History  |
|    102 | Somil  | Computer |
|    103 | Rahul  | DBMS     |
|    104 | Aarav  | History  |
+--------+--------+----------+
5 rows in set (0.00 sec)

现在，借助下面的查询，我们可以比较这些表并获取不匹配的行作为结果集。

mysql> Select RollNo,Name,Subject from(select RollNo,Name,Subject from students union all select RollNo,Name,Subject from Student1)as std GROUP BY RollNo,Name,Subject HAVING Count(*) = 1 ORDER BY RollNo;
+--------+-------+---------+
| RollNo | Name  | Subject |
+--------+-------+---------+
|    103 | Rahul | DBMS    |
|    104 | Aarav | History |
+--------+-------+---------+
1 rows in set (0.02 sec)